Normal distribution

$\mu$
$\sigma$
$$ f(x)=\frac{1}{\sigma\sqrt{2\pi}}\exp\bigg(-\frac{1}{2}\big(\frac{x-\mu}{\sigma}\big)^2\bigg) \\[16pt] \text{where $\mu$ is the mean and $\sigma$ is the standard deviation.} $$